Features of DumpsActual 1z1-071 PDF and Practice Exams
Features of DumpsActual 1z1-071 PDF and Practice Exams
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Oracle Database SQL Sample Questions (Q44-Q49):
NEW QUESTION # 44
View the exhibit and examine the structure and data in the invoice table. (Choose two.)
Which two SQL statements would execute successfully?
- A. SELECT AVG(inv_date) FROM invoice
- B. SELECT MAX(AVG(SYSDATE -inv_date)) FROM invoice
- C. SELECT AVG( inv_date -SYSDATE), AVG(inv_amt) FROM invoice
- D. SELECT MAX(inv_date), MIN(cust_id) FROM invoice
Answer: C,D
NEW QUESTION # 45
Which two will execute successfully?
- A. SELECT NVL('DATE',SYSDATE) FROM DUAL;
- B. SELECT NVL('DATE',200) FROM (SELECT NULL AS "DATE" FROM DUAL);
- C. SELECT COALESCR('DATE', SYSDATE) FROM DUAL;
- D. SELECT COALESCE('DATE',SYSDATE) FROM (SELECT NULL AS "DATE" FROM DUAL) ;
- E. SELECT COALESCE(O,SYSDATE) TRCH DUAL;
Answer: A,B
NEW QUESTION # 46
Which two are true about self joins?
- A. They are always equijoins.
- B. They have no join condition.
- C. They require the NOT EXISTS operator in the join condition.
- D. They require the EXISTS opnrator in the join condition.
- E. They can use INNER JOIN and LEFT JOIN.
- F. They require table aliases.
Answer: E,F
NEW QUESTION # 47
View the exhibit and examine the structures of the EMPLOYEESand DEPARTMENTStables.
EMPLOYEES
Name Null? Type
- ---------------- ----- -------------
EMPLOYEE_ID NOT NULL NUMBER(6)
FIRST_NAME VARCHAR2(20)
LAST_NAME NOT NULL VARCHAR2(25)
HIRE_DATE NOT NULL DATE
JOB_ID NOT NULL VARCHAR2(10)
SALARY NUMBER(10,2)
COMMISSION NUMBER(6,2)
MANAGER_ID NUMBER(6)
DEPARTMENT_ID NUMBER(4)
DEPARTMENTS
Name Null? Type
----------------- ----- -------------
DEPARTMENT_ID NOT NULL NUMBER(4)
DEPARTMENT_NAME NOT NULL VARCHAR2(30)
MANAGER_ID NUMBER(6)
LOCATION_ID NUMBER(4)
You want to update EMPLOYEEStable as follows:
Update only those employees who work in Boston or Seattle (locations 2900 and 2700).
Set department_idfor these employees to the department_idcorresponding to London
(location_id 2100).
Set the employees' salary in location_id2100 to 1.1 times the average salary of their department.
Set the employees' commission in location_id2100 to 1.5 times the average commission of their
department.
You issue the following command:
SQL> UPDATE employees
SET department_id
( SELECT department_id
FROM departments
WHERE location_id = 2100),
( salary, commission)
( SELECT 1.1*AVG(salary), 1.5*AVG(commission)
FROM employees, departments
WHERE departments.location_id IN(2900, 2700, 2100))
WHERE department_id IN
( SELECT department_id
FROM departments
WHERE location_id = 2900
OR location_id = 2700;
What is outcome?
- A. It generates an error because multiple columns (SALARY, COMMISSION)cannot be specified together in an UPDATEstatement.
- B. It executes successfully but does not give the desired update
- C. It generates an error because a subquery cannot have a join condition in a UPDATEstatement.
- D. It executes successfully and gives the desired update
Answer: B
NEW QUESTION # 48
View the Exhibit and examine the structure of ORDERS and CUSTOMERS tables. (Choose the best answer.)
You executed this UPDATE statement:
Which statement is true regarding the execution?
- A. It would not execute because a subquery cannot be used in the WHERE clause of an UPDATE statement.
- B. It would not execute because a SELECT statement cannot be used in place of a table name.
- C. It would not execute because two tables cannot be referenced in a single UPDATE statement.
- D. It would execute and restrict modifications to the columns specified in the SELECT statement.
Answer: D
NEW QUESTION # 49
......
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